Question

Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung. The sum of the all three ages is 135 years. What is the age of each one of them???????? ​

Answer 1

Answer:

Step-by-step explanation:

B GRAND FATHER=B FATHER+26

B FATHER=B+29

NOW,

B GRAND FATHER+B FATHER+B=135

SO,

B+29+26=B GRAND FATHER

NOW YOU CAN FIGURE OUT THE QUESTION I GAVE THE MAIN IDEA..

Answer 2

Answer:

Baichung is 17 yrs. old

His father is 46 yrs. old

His grandfather is 72 yrs old

Step-by-step explanation:

Let age of Baichung be x then

According to the question

Baichung's father's age = x + 29

also Baichung's father is 26 years younger than Baichung's grandfather

therefore age of Baichung's grandfather = x + 29 +26

                                                                    = x + 55

Also the sum of the ages of all three = 135

therefore,

Baichung's age+ Baichung's father's age+ Baichung's grandfather's age= 135

$x + (x + 29) + (x + 55) = 135\\x + x + 29 + x + 55 = 135\\3x + 84 = 135\\3x = 135 - 84\\3x = 51\\x = \frac{51}{3} = 17$

therefore,

Baichung is 17 yrs. old

His father is x + 29 = 17 +29 = 46 yrs. old

His grandfather is x + 55 = 17 + 55 = 72 yrs old