Math, asked by roopamjunghare, 4 months ago

Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung. The sum of all three is 135 years. What is the age of each one of them?

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Answers

Answered by santhozh06
1

Answer:

let us take baichung father =x

so,

baichung age =x-29

baichung grandfather age =x+26

so the sum of the three ages = x+ (x+26)+(x-29)

135=3x-3

138=3x

x=46

so,baichung father's age =46

baichung age =17

baichung grandfather age = 72

Answered by ItzEnchantedGirl
0

Answer:

Given :

Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .

The sum of the age of all the three is 135 years.

Solution :

\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}

\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}

A.T.Q :

\longmapsto\tt{x+x-26+x-55=135}

\longmapsto\tt{3x-81=135}

\longmapsto\tt{3x=135+81}

\longmapsto\tt{3x=216}

\longmapsto\tt{x=\cancel\dfrac{216}{3}}

\longmapsto\tt\bf{x=72}

Value of x is 72 .

Therefore :

\longmapsto\tt{Age\:of\:his\:Grandfather=x}

\longmapsto\tt\bf{72\:yrs}

\longmapsto\tt{Age\:of\:his\:Father=72-26}

\longmapsto\tt\bf{46\:yrs}

\longmapsto\tt{Age\:of\:Baichung=72-55}

\longmapsto\tt\bf{17\:yrs}

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