Question

A ball is dropped from height h.when it reaches the ground its velocity is 40m/s find h​

Answer 1

Answer:

height is 80m

Explanation:

v=40 m/s

u=0m/s

g=10m/s^2

so

By 3rd eq. of motion

V^2-U^2=2×G×H

40^2-0^2=2×10×H

1600=20×H

H=1600/20

H=80m

Answer 2

Explanation:

h=?

u=0m/s

v=40m/s

g=10m/s2

2gh=40×40-0

2×10h=1600

20h=1600

h=1600÷20

=80m