Question

Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung.The sum of the ages of all three is 135 years. What is the age of each one of them?


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Answer 1

Answer:

Age of Baichung's father = x = 46

then, Age of Baichung's grandfather = x+26 = 46+26 = 72

so, Age of Baichung = x-29 = 46-29 = 17

Explanation:

Let the age of Baichung's father be = x

Then, the age of Baichung's grandfather = x+26

So, the age of Baichung = x-29

 

$x+(x+26)+(x-29) = 135\\= 3x+(26-29)\\= 3x -3 = 135\\3x = 135+3\\3x =138\\then, x = \frac{138}{3}\\x = 46$

∴ Age of Baichung's father = x = 46

then, Age of Baichung's grandfather = x+26 = 46+26 = 72

so, Age of Baichung = x-29 = 46-29 = 17

Hope it helpss :)

Answer 2

Answer:

Given :

Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .

The sum of the age of all the three is 135 years.

Solution :

$\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}$

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

$\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}$

$\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}$

A.T.Q :

$\longmapsto\tt{x+x-26+x-55=135}$

$\longmapsto\tt{3x-81=135}$

$\longmapsto\tt{3x=135+81}$

$\longmapsto\tt{3x=216}$

$\longmapsto\tt{x=\cancel\dfrac{216}{3}}$

$\longmapsto\tt\bf{x=72}$

Value of x is 72 .

Therefore :

$\longmapsto\tt{Age\:of\:his\:Grandfather=x}$

$\longmapsto\tt\bf{72\:yrs}$

$\longmapsto\tt{Age\:of\:his\:Father=72-26}$

$\longmapsto\tt\bf{46\:yrs}$

$\longmapsto\tt{Age\:of\:Baichung=72-55}$

$\longmapsto\tt\bf{17\:yrs}$