baichung 's father is 26years younger than baichung 's father and 29 years older than baichung . the sum of the ages of all the three is 135years .what is the age of each one of them?
Answers
bainchungs grandfathers age= x+26+29= x+55
bainchungs fathers age= x+29
therefore,
x+x+55+x+29= 135
= 3x + 84 = 135
=3x = 51
= x = 51/3= 17
therefore
bichungs age = 17
bainchungs fathers age = 17+29= 46
bainchungs grandfathers = 17+55= 72
Let the age of Baichung’s father = m year
Since, Baichung’s father is 26 year younger than Baichung’s grand father
Therefore, Age of Baichung’s grandfather = Age of Baichung’s father + 26 = m + 26 year
Since, Baichung’s father is 29 year older than Baichung
Therefore, Age of Baichung = Age of Baichung’s father – 29 = m – 29 year
Now, we have
Age of Baichung = m – 29 year
Age of Baichung’s father = m year
Age of Bahichung’s grandfather = m + 26 year
According to question, the sum of ages of all the three = 135 year
Therefore,
Age of Baichung + Age of Baichung’s father + Age of Baichung’s grandfather = 135
⇒ (m – 29) + m + (m + 26) = 135 year
⇒ m – 29 + m + m + 26 = 135 year
⇒ m + m + m – 29 + 26 = 135 year
⇒ 3m – 3 = 135 year
After transposing – 3 to the RHS, we get
3m = 135 year + 3
⇒ 3m = 138 year
After dividing both sides by 3, we get
This means age of Baichung’s father = 46 year
Now, by substituting the value of m, we can calculate the age of Baichung and the age of Baichun’s grandfather.
Therefore,
Age of Baichung = m – 29 = 46 – 29 = 17 year
Age of Baichung’s grandfather = m + 26 = 46 + 26 = 72 year
Thus,
Age of Baichung = 17 year
Age of Baichung’s father = 46 year
Age of Baichung’s grandfather = 72 year
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