Math, asked by Watcher, 10 months ago

Baichung's father is 26yrs younger than Baichung's grandfather and 29yrs older than Baichung.The sum of the age of all the age is 135yrs.What is the age of each one of them?

Answers

Answered by Abhiram2830r
1

Answer:

56

Step-by-step explanation:

Answered by Anonymous
0

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Let the age of Baichung’s father = m year

Since, Baichung’s father is 26 year younger than Baichung’s grand father

Therefore, Age of Baichung’s grandfather = Age of Baichung’s father + 26 = m + 26 year

Since, Baichung’s father is 29 year older than Baichung

Therefore, Age of Baichung = Age of Baichung’s father – 29 = m – 29 year

Now, we have

Age of Baichung = m – 29 year

Age of Baichung’s father = m year

Age of Bahichung’s grandfather = m + 26 year

According to question, the sum of ages of all the three = 135 year

Therefore,

Age of Baichung + Age of Baichung’s father + Age of Baichung’s grandfather = 135

⇒ (m – 29) + m + (m + 26) = 135 year

⇒ m – 29 + m + m + 26 = 135 year

⇒ m + m + m – 29 + 26 = 135 year

⇒ 3m – 3 = 135 year

After transposing – 3 to the RHS, we get

3m = 135 year + 3

⇒ 3m = 138 year

After dividing both sides by 3, we get

This means age of Baichung’s father = 46 year

Now, by substituting the value of m, we can calculate the age of Baichung and the age of Baichun’s grandfather.

Therefore,

Age of Baichung = m – 29 = 46 – 29 = 17 year

Age of Baichung’s grandfather = m + 26 = 46 + 26 = 72 year

Thus,

  • Age of Baichung = 17 year

  • Age of Baichung’s father = 46 year

  • Age of Baichung’s grandfather = 72 year

Hope it helps you!

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