Math, asked by sasd71, 10 months ago

Baichungs father is 26 years younger than baichungs grandfather and 29 years older than baichung.the sum of the ages of all three is 135 years. what is the age of each one of them?​

Answers

Answered by anusuya61
1

Answer:

answer,

baichung's age = 17 yr

baichung's father's age = 46 yr

baichung's grand father age = 72

Step-by-step explanation:

baichung's age =x

baichung's father's age= baichung's grand father age -26

x+29=baichung's grand father age -26

x+29+26= b.g.f

x+55=b.g.f

baichung's grand father age = x + 55

given ,

x+29+x+55=135

3x+84 =135

3x=135-84

3x=51

x=51/3

x=17

therefore,

baichung's age=17 yr

baichung's father's age= 46 yr

baichung's grand father age= 72 yr

Answered by XxxRAJxxX
1

Let the age of Baichung’s father be x.

Then, the age of Baichung’s grandfather = (x+26)

and, Age of Baichung = (x-29)

According to the question,

x + (x+26) + (x-29) = 135

⇒ 3x + 26 – 29 = 135

⇒ 3x – 3 = 135

⇒ 3x = 135 + 3

⇒ 3x = 138

⇒ x = 138/3

⇒ x = 46

Age of Baichung’s father = x = 46

Age of Baichung’s grandfather = (x+26) = 46 + 26 = 72

Age of Baichung = (x-29) = 46 – 29 = 17

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