Question

Baichungs father is 26 years younger than baichungs grandfather and 29 years older than baichung.the sum of the ages of all the three is 135 years. what is the age of each one of them?​

Answer 1

Answer:

Let

Baichungs father's age=x. years

${:}\longrightarrow$Baichungs grandfather's age=(x+26)years

${:}\longrightarrow$Baichungs age=(x-29)years

Now,

According to the question

${:}\longrightarrow$The sum of the ages of all three is 135years

${:}\longrightarrow$$x+(x+26)+(x-29)=135$

${:}\longrightarrow$$x+x+26+x-29=135$

${:}\longrightarrow$$x+x+x+26-29=135$

${:}\longrightarrow$$3x-3=135$

${:}\longrightarrow$$3x=135+3$

${:}\longrightarrow$$3x=138$

${:}\longrightarrow$$x={\frac {138}{3}}$

${:}\longrightarrow$${\underline{\boxed{\bf {x=46}}}}$

Hence,

Baichung's fathers age=x=46years

Baichung's grandfather's age=(x+26)=46+26=72years

Baichung's age=(x-29)=46-29=17years

Answer 2

Given :

Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .

The sum of the age of all the three is 135 years.

Solution :

$\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}$

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

$\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}$

$\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}$

A.T.Q :

$\longmapsto\tt{x+x-26+x-55=135}$

$\longmapsto\tt{3x-81=135}$

$\longmapsto\tt{3x=135+81}$

$\longmapsto\tt{3x=216}$

$\longmapsto\tt{x=\cancel\dfrac{216}{3}}$

$\longmapsto\tt\bf{x=72}$

Value of x is 72 .

Therefore :

$\longmapsto\tt{Age\:of\:his\:Grandfather=x}$

$\longmapsto\tt\bf{72\:yrs}$

$\longmapsto\tt{Age\:of\:his\:Father=72-26}$

$\longmapsto\tt\bf{46\:yrs}$

$\longmapsto\tt{Age\:of\:Baichung=72-55}$

$\longmapsto\tt\bf{17\:yrs}$