Question

Balance cr2o72- + so2 gives cr3+ + so42-

Answer 1

Answer:

The reaction we are given here to Balance $Cr_{2}{O_{7}}^{2-} + SO_{2}$gives cr_{3}+ + $SO_{4}^{2-}$ is basically an example or a type of redox reaction.

In other words we can say there are two types of half reactions that has been taking place in the above given reaction one that has oxidation happening in it and other half has reduction happening in it.

So the two reactions to balance the equation would be  

$Cr_{2}{O_{7}}^{2-} + 14 H_{2}O + 6e^- \rightarrow 2Cr_{3}+ + 7H_{2}O + 14OH^-$

$3{SO_{3}}^{2-} + 3H-{2}O + 6OH^- \rightarrow 3SO_{4}^{2-} + 6H_{2}O + 6e^-$

Show the final balanced equation will be

$3SO_{3}2^- + Cr_{2}{O_{7}}^{2-} + 4H_{2}O \rightarrow 2Cr_{3}+ + 3SO_{4}^{2-} + 8OH^-$

To know more:

Cr2O7 2-+ SO3 2-GIVES RISE TO Cr 3+ SO4 2- BALANCE BY OXIDATION NUMBER METHOD

https://brainly.in/question/1060762

Balance the following redox reactions by ion-electron method:

(a) MnO4(-) (aq) + I– (aq)→MnO2 (s) + I2(s) (in basic medium)

(b) MnO4(-) (aq) + SO2 (g)→Mn2+ (aq) + HSO4(-) (aq) (in acidic solution)

(c) H2O2 (aq) + Fe2+ (aq)→Fe3+ (aq) + H2O (l) (in acidic solution)

(d)Cr2O7(2-) + SO2(g)→Cr3+ (aq) + SO4(2-) (aq) (in acidic solution)

https://brainly.in/question/8125962