Balance equation.
Potassium permanganete +hydrochloric acid =
Potassium chloride +manganese chloride +
Chlorine + water
Answers
This is a classic redox problem involving MnO4- . The key to it is the ionic form of the redox equation for this ion which is:
8 H+ + MnO4- + 5 e- → Mn2+ + 4 H2O
Since we are forming molecular Cl2 , we need another redox ionic equation
2 Cl- → Cl2 + 2 e-
Since the e- must cancel out when we combine these equations, we need to multiply the first one by 2
and multiple the second one by 5 and then combine to get
16 H+ + 2 MnO4- + 10 Cl- → 2 Mn2+ + 8 H2O + 5 CL2
This is the hard part. The rest is just a matter of adding the two K+ ions to each side and six more Cl- ions to each side to take care of the MnCl2 and KCl that will be on the right hand side.
The final result is:
2 K MnO4 + 16 HCl → 2 MnCl2 + 5 Cl2 + 2 KCl + 8 H2O
Answer:
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Explanation:
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