Question

Balance the equation by oxidation number method:--- N2H4 (g) + ClO3^- (aq) -------> NO (g) + Cl^- ( aq)

Answer 1

●OXIDATION REACTION :-

N2H4 ----> NO

[1st step]

● First balance the nitrogens :-

N2H4 ---> 2N0
___________

[2nd step]

●Next balance balance the oxygens by adding water :-

N2H4 + 2H2O -----> 2NO
___________

[3rd step]

●balance the hydrogens by adding H+

N2H4 + 2H2O ----> 2NO + 8H+
___________

[4th step]

●Finally balance the charge by adding electrons :-

N2H4 + 2H2O ---> 2NO + 8H+ 8e-

________________________________

NOW

●REDUCTION REACTION :-

[1st step]

ClO3(-) ----> Cl(-)
_____________

[2nd step]

ClO3(-) ----> Cl(-) + 3H2O
_____________

[3rd step]

ClO3(-) + 6H+ -----> Cl(-) + 3H2O
_____________

[4th step]

ClO3(-) + 6H+ + 6e(-) ----> Cl(-) + 3H2O

___________________________________-

●Finally we are combined the two reaction ,
we get.. but we need to have the no. of electron to be equal in both half reaction , so we multiply oxidizing reaction by 3 and reduction reaction by 4

after that,

●Combined and canceling out the common product we get final balanced reaction

◢FINAL REACTION :-

3N2H4 + 4ClO3(-) ----> 6NO + 4Cl(-) + 6H2O

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_-_-_-_☆$BE \: \: \: \: BRAINLY$☆_-_-_-_

Answer 2

Heya....✋
Answer is in attachment
hope it helps✅