balance the equation H2S + KMnO4 + H2 S o4 gives khso4 + mnso4 + S + H2O
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Answer:
2KMnO4 + 3H2SO4 +5H2S > K2SO4 + 2MnSO4+8H2O+5S
Explanation:
Reduction reaction:
MnO4- + 5e- + 8 H+ > Mn2+ 4 H2O............(i)
Oxidation reaction :
S2- – 2e- > S....................(ii)
Now,
(i)×2 + (ii)× 5 >
2MnO4- + 10e- + 16H+ > 2Mn2+ 8H2O
5S2- – 10e- > 5S
Total raction
2MnO4- + 16H+ + 5S2- > 2Mn2+ 8H2O + 5S
Then both sides additng ( K+, SO4 2-)
2KMnO4 + 3H2SO4 +5H2S > K2SO4 + 2MnSO4+8H2O+5S
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