Question

Balance the equation Potassium iodide+manganese dioxide+sulphuric acid gives out Iodine+potassium hydrogen sulphate+manganese sulphate+water

Answer 1

The equation should be
2KI + MnO2 + 3H2SO4 = I2 + 2H2O + 2KHSO4 + MnSO4  
where iodine will be evaporated

Answer 2

Balancing equation

Explanation:

• In the given reaction, the reactants are:

1. Potassium iodide (PI),
2. Manganese dioxide ($MnO_2$)
3. Sulfuric acid $(H_2SO_4)$  

• The products formed are as follows:

1. Iodine (I)
2. Potassium hydrogen sulfate ($KHSO_4$)
3. Manganese sulfate ($MnSO_4$)
4. Water ($H_2O$)

• The chemical equation involved is

$KI+MnO_2+H_2SO_4\rightarrow H_2O+KHSO_4+MnSO_4+I_2$

• In the balanced reaction the number of atoms involved in reaction in reactants as well as the product is equal.

• As the number of atoms involved in reaction in reactants as well as the product is not equal, some changes must be made.
• Thus the balanced equation for the given reaction is:

$2KI+MnO_2+3H_2SO_4\rightarrow 2H_2O+2KHSO_4+MnSO_4+I_2$

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