balance the following chemical equation by partial equation method KMnO4 + H2 s o4 + H2 C2 o4 arrow k 2 s o4 + mnso4 + H2O + c02 in chemistry
Answers
Answered by
0
Explanation:
+1
KM
+7
nO
4
−2
+
+3
C
2
O
4
−2
H
2
+1
+
1
H
2
S
6
O
4
−2
⇌
1
K
2
S
6
O
4
−2
+
2
MnS
8
O
4
−2
+
4
CO
2
−2
+
1
H
2
O
−2
Oxidation:
3
C
2
O
4
−2
H
2
1
⟶2
C
6
O
2
−2
+2e
−
Reduction: KMnO
4
⟶Mn
+2
S
6
O
4
−2
⇒ O: C
2
O
4
H
2
⟶2CO
2
+2e
−
+2H
+
R: 2KMnO
4
+3H
2
SO
4
+10e
−
+10H
+
⟶2MnSO
4
+K
2
SO
4
+8H
2
O
⇒ O: 5C
2
O
4
H
2
⟶10CO
2
+10e
−
+10H
+
R: 2KMnO
4
+3H
2
SO
4
+10e
−
+10H
+
⟶2MnSO
4
+K
2
SO
4
+8H
2
O
∴5C
2
O
4
H
2
+2KMnO
4
+3H
2
SO
4
⟶2MnSO
4
+10CO
2
+K
2
SO
4
+8H
2
O .
Similar questions