Question

Balance the following chemical equations.
(a) Fels) + H₂O(g) resouls) + H₂(g)
(b) A 1134 H₂ Soy Laaj
Ale (sou) las) of H₂
buch
(es C2H61) + O2
CO2(g) + H₂O (9)​

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

Writing the oxidation numbers of the atoms.

HgS+2+2+HCl+1−1+HNO3+1+5−2→H2HgCl4+1+2−1+NO+2−2+S0+H2O+1−2

The oxidation number of S and N have changed

HgS−2→S0...(i)

HNO3+5→NO+2....(ii)

Increase in Ox. no. of S=2 units per HgS molecule

Decrease in Ox. no of N=3 units per HNO3 molecule

Multiplying eq. (i) by 3 and eq. (ii) by 2 as to make increase and decrease equal.

3HgS+2HNO3→3S+2NO

Balancing Hg and chlorine.

3HgS+2HNO3+12HCl→3H2HgCl4+3S+2NO

To balance hydrogen and oxygen, 4H2O molecules are added on RHS. Hence, the balanced equation is.

3HgS+2HNO3+12HCl→3H2HgCl4+3S+2NO+4H2O