Question

balance the following equation
​

Answer 1

1)   the 1st one is already balanced.

2)  2KClO3 → 2KCl +  3O2

3)   2NaCl + F2 → 2NaF + Cl

4)   2H2 + O2 →2H2O.

5)   2Pb ( OH ) 2 + 2HCl → 2H2O + PbCl2

6)  2AlBr3 + 3K2SO4 → 6KBr + Al2 ( SO4 ) 3

7)   CH4 + 2O2 → CO2 + 2H2O

8)   C3H8 + 5O2 → 3CO2 + 4H2O

procedure to balance any equation

Step 1 : on one side write the reactants and on other side write down the products. Now write the number of the molecules of the reactants and also the products.

example : N2 + H2 → NH3

  reactants                                               products

N  - 2                                                       N - 1

H  - 2                                                        H - 3

Step 2 : try to balance the number of molecules. Like u have 2 molecules of nitrogen in reactants side , whereas only 1 molecule of nitrogen in products side. To get 2 molecules of nitrogen in product side you will have to put 2 in front of NH3 , so what will happen is , you will multiply that 2 to 1 nitrogen molecule which will get u 2 molecules of nitrogen.

Now you will see that hydrogen molecules become 6 from 3 , why? becoz you multiplied that front 2 to that down 3 so u get 6.

reactants                                                  products

N - 2                                                          N - 2

H - 2                                                          H - 6

Step 3 : Now you will put 3 to get 6 molecules of Hydrogen in front of H2 in reactants side, so u will basically multiply that front 3 to the down 2 to get 6

So now u see all the molecules : reactants and products are now balanced.

Now u get a proper balanced equation

N2 + 3H2 → 2NH3

Actually I preferred to explain u the steps so that i future whenever u go to solve / balance equations it will be easy for u.

please dont take it wrong.

please give it a brainly mark

I hope u understood my explanation, acc to me this was the easiest one