Balance the following equation
a) Fe+O₂ Fey 0.
b) Zn SO+NH,OH (NH)2 SO4 + Zn(OH)₂2
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Answer:
a)Step 1: Tally the number of atoms based on subscript.
Fe+O2→Fe2O3 (unbalanced)
left side: Fe=1;O=2
right side: Fe=2;O=3
Step 2: Start balancing the simple molecules first, in this case the O2
Fe+3O2→Fe2O3
left side: Fe=1;O=2×3=6
right side: Fe=2;O=3
Since there are now 6 O atoms on the left, there must also be 6 O atoms on the right. Notice that the right hand is one big molecule so whatever coefficient we would use to balance the O atoms, we would also need to apply to the bonded Fe atom.
Fe+3O2→2Fe2O3
left side: Fe=1;O=2×3=6
right side: Fe=2×2=4;O=3×2=6
Step 3: Now balance the rest of the equation.
4Fe+3O2→2Fe2O3
left side: Fe=1×4=4;O=2×3=6
right side: Fe=2×2=4;O=3×2=6
The equation is now balanced.
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