Balance the following equation
C2H5OH + I2 + OH- —>CHI3 + HCOO- + I-
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Balanced Chemical Equation :
C2H5OH + 4I2 + 2OH- → 2CHI3 + 2I- + 3H2O
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Ethanol + Diiodine + Hydroxide Ion = Iodoform + Iodide Ion + Water
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➡️Carbon is oxidized from the -2 to the +2 state. Iodine is reduced from the zero state to the -1 stateSince carbon is being oxidized, then iodine is reduced, and iodine can only be reduced to -1. The problem is that carbon is oxidized from -2 to +2 in both CHI3 and HCOO-. The final equation is ... C2H5OH + 4I2 + 6OH- --> CHI3 + HCOO- + 5I- + 5H2O
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