Question

Balance the following equation -
_C6H12O6 + _O2 → _H20 + _CO2

Answer 1

Answer:

C6H12O6 + 6O2 -> 6H2O + 6CO2

Explanation:

When balancing an equation, leave the element that occurs more than once on a side for last. (In this occasion, O.)

So, I started with C. On the left side, there are 6 C, but on the right side, there is only 1 C. To fix this, I put a 6 in front of the CO2, changing the number of C molecules to 6 and the number of oxygen molecules from 2 to 12.  _C6H12O6 + _O2 -> _H20 + 6CO2

Then, I moved to H. On the left side, there are 12 H, but on the right side, there are only 2 H. So, I put a 6 in front of the H in order to multiply the 2 by 6,   which changed the number of H molecules to 12 and the number of O molecules from 1 to 6. _C6H12O6 + _O2 -> 6H20 + 6CO2

Lastly is O. On the left side there is 6 O molecules stuck to the only C and H molecules, so it is in our best interest to leave it alone, lest the whole equation be changed. Also on the left side is 2 O molecules that can be changed without risk. On the right side, we have 6 O molecules from the H2O and 12 O molecules from the CO2, but it is also known that there are 6 O molecules on the left side that we cannot change. Basically, what is left is 2 times _ = 12. The answer is 6, so the equation is as follows, C6H12O6 + 6O2 -> 6H2O + 6CO2

Answer 2

C6H12O6+6O2=6H2O+6CO2