Question

Balance the following equations by oxidation number method
i) K,Cr,O, + KI + H2SO4 → K2SO4 + Cr2(SO4)3 +I2+H2O​

Answer 1

Answer:

This is an oxidation-reduction (redox) reaction:

6 I-I - 6 e- → 6 I0 (oxidation)

2 CrVI + 6 e- → 2 CrIII (reduction)

KI is a reducing agent, K2Cr2O7 is an oxidizing agent.

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