balance the given equation
CO2+O2--------CO
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NO. OF OXYGEN AT REACTANTS IS 4
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
SO , FOR BALANCING OXYGEN AT THE PRODUCT SIDE MULTIPLY IT BY 4 .....
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
YOU WILL GET ....
CO2 + O2 ===> 4 ( CO )
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
NOW ,
NO. OF CARBON ATOMS IN PRODUCT SIDE IS 4 AND THUS YOU SHOULD MULTIPLY THE CARBON ATOMS AT REACTANTS BY 4
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
YOU WILL GET ,
4 ( CO2 ) + O2 ====>. 4 ( CO )
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
NOW NO. OF OXYGEN IN REACTANT IS 10.....
SO TO BALANCE THE OXYGEN MULTIPLY PRODUCT SIDE BY 4/10 ......
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
I THINK THIS WON'T STOP ....
THIS WILL BE CONTINUE......
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
HOPE U HAVE UNDERSTOOD HOW TO DO IT....
THAT IS IMP.
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
THANKS !
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
SO , FOR BALANCING OXYGEN AT THE PRODUCT SIDE MULTIPLY IT BY 4 .....
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
YOU WILL GET ....
CO2 + O2 ===> 4 ( CO )
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
NOW ,
NO. OF CARBON ATOMS IN PRODUCT SIDE IS 4 AND THUS YOU SHOULD MULTIPLY THE CARBON ATOMS AT REACTANTS BY 4
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
YOU WILL GET ,
4 ( CO2 ) + O2 ====>. 4 ( CO )
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
NOW NO. OF OXYGEN IN REACTANT IS 10.....
SO TO BALANCE THE OXYGEN MULTIPLY PRODUCT SIDE BY 4/10 ......
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
I THINK THIS WON'T STOP ....
THIS WILL BE CONTINUE......
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
HOPE U HAVE UNDERSTOOD HOW TO DO IT....
THAT IS IMP.
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
THANKS !
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