q. Two point charges of +16 micro coulomb and -9 micro coulomb are placed 8 cm apart in air .Determine the position of the point at which the resultant field is zero .
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Because both charge have opposite sign therefore we can say that the position of E=0 at between the two charges.
We assume that the charge (a)q1=16micro C
(b)q2=-9micro C
X is the distance between q1 and the point where E=0 (Consider C)
ac=x
bc=8-x
Now applying E1+E2=0(according to question)
Kq1/x²+kq2/(8-x)²=0 X=32/7
We assume that the charge (a)q1=16micro C
(b)q2=-9micro C
X is the distance between q1 and the point where E=0 (Consider C)
ac=x
bc=8-x
Now applying E1+E2=0(according to question)
Kq1/x²+kq2/(8-x)²=0 X=32/7
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