Balance the reaction
KOH + K4Fe(CN)6 + Ce(NO3)4 giving Ce(OH)3 + Fe(OH)3 + K2CO3 + KNO3 + H2O
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Answer:
KOH + K4Fe(CN)6 + Ce(NO3)4 giving Ce(OH)3 + Fe(OH)3 + K2CO3 + KNO3 + H2O
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ADD ANSWER258KOH + K4(Fe(CN)6) + 61Ce(NO3)4 → Fe(OH)3 + 61Ce(OH)3 + 6K2CO3 + 250KNO3 + 36H2O
Explanation:
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upper baka this ha hope you understand
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