Question

Balance the redox equation by ion - electron method taking place in basic medium
Cr(OH)3 + IO3 → CrO4 + I

Answer 1

Answer:

solution 1: Cr⁺³ (O⁻²H⁺¹)3 + I⁺³O3⁻¹ --> Cr⁺⁴O4⁻¹ + I⁰

6Cr(OH)3 + 5IO3 --> 6CrO4 + 5I + 9H2O

solution 2 : Cr⁺³ (O⁻²H⁺¹)3 + I⁺³O3⁻¹ --> Cr⁻⁴O4⁺¹ + I⁰

13IO3 + 12Cr(OH)3 + 18e⁻ ---> 12CrO4 + 13I + 9H2O + 18OH⁻

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hi there, take a look at that s!te called periodni. they give very well explained step-by-step solutions.

I haven't learned this yet so I have some limitations. really sorry for that.

oh and I'm doing good. hope you are doing good as well ♡