Question

Balance the redox reaction by oxidation number or ion electron method: K2Cr2O7 + Sncl2 + HCl = CrCl3 +SnCl4 + KCl + H2O

Answer 1

Answer:

HERE IS UR ANSWER

Explanation:

K2Cr2O7 + 3 SnCl2 + 14 HCl → 3 SnCl4 + 2 CrCl3 + 2 KCl + 7 H2O

This is an oxidation-reduction (redox) reaction:

3 SnII - 6 e- → 3 SnIV (oxidation)

2 CrVI + 6 e- → 2 CrIII (reduction)

SnCl2 is a reducing agent, K2Cr2O7 is an oxidizing agent.

HOPE IT HELPED YOU

THANK YOU