Question

Balance the redox reaction in acidic medium mno4(aq) + io3(aq) → mno2 (s) + io4 (aq).
answer this u will get 50 pts

Answer 1

Answer:

Step 1: Write equation

MnO4 (aq) + IO3 (aq) ---> MnO2 (s) + IO4 (aq)

Step 2: Balance unbalanced equation

Already balanced.

Steps 3 & 4: Find oxidation numbers and determine the change in oxidation numbers.

Mn starts with +7 and ends with +4; this is reduction.

I starts with +5 and ends with +7; this is oxidation.

Step 5: Find the net changes of the oxidation numbers, than multiple the oxidized and reduced atoms with least common multipliers.

Mn has a net change of 3, so multiply the I atoms by 3.

I has a net change of 2, so multiply the Mn atoms by 2.

2[MnO4 (aq)] + 3[IO3 (aq)] ---> 2[MnO2 (s)] + 3[IO4 (aq)]

Step 6: Balance for O by adding H2O to the side with the least amount of O, and then balance for H by adding H+ to the side with the least amount of H.

2H + 2[MnO4 (aq)] + 3[IO3 (aq)] ---> 2[MnO2 (s)] + 3[IO4 (aq)] + H2O

Answer 2

Answer:

6MnO4- + I- + 6OH- → 6MnO42- + IO3- + 3H2O