Question

balance this redox reaction ​

Answer 1

I-

I-Cr(OH)3 GIVES Cr+3 + 3OH-

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic medium

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now IO3 - ----->I-

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now IO3 - ----->I-IO3 - +3H2O ----> I- + 6OH-

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now IO3 - ----->I-IO3 - +3H2O ----> I- + 6OH- IO3- + 3H2O + 6e- -----> I- +6OH- Tthis is our second equation

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now IO3 - ----->I-IO3 - +3H2O ----> I- + 6OH- IO3- + 3H2O + 6e- -----> I- +6OH- Tthis is our second equation

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now IO3 - ----->I-IO3 - +3H2O ----> I- + 6OH- IO3- + 3H2O + 6e- -----> I- +6OH- Tthis is our second equation Multiplying first euation with three and second equation with six

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now IO3 - ----->I-IO3 - +3H2O ----> I- + 6OH- IO3- + 3H2O + 6e- -----> I- +6OH- Tthis is our second equation Multiplying first euation with three and second equation with six We get our equation as

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now IO3 - ----->I-IO3 - +3H2O ----> I- + 6OH- IO3- + 3H2O + 6e- -----> I- +6OH- Tthis is our second equation Multiplying first euation with three and second equation with six We get our equation as 3IO3- + 9H2O+6Cr(OH)3------> 6(Cro4)2- +24H2O + 3I- + 18OH-

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now IO3 - ----->I-IO3 - +3H2O ----> I- + 6OH- IO3- + 3H2O + 6e- -----> I- +6OH- Tthis is our second equation Multiplying first euation with three and second equation with six We get our equation as 3IO3- + 9H2O+6Cr(OH)3------> 6(Cro4)2- +24H2O + 3I- + 18OH-Then by simplifying we get he balanced equation as

I-Cr(OH)3 GIVES Cr+3 + 3OH- Hear OH shows that the equation should be balanced in basic mediumCr+3----->(Cro4)2-Cr+3----->(Cro4)2- +4H2O8OH- + Cr+3---->(Cro4)2- + 4H2O 8OH- + cr+3--->4H2O+(Cro4)2-+ 3e- this is our first equation Now IO3 - ----->I-IO3 - +3H2O ----> I- + 6OH- IO3- + 3H2O + 6e- -----> I- +6OH- Tthis is our second equation Multiplying first euation with three and second equation with six We get our equation as 3IO3- + 9H2O+6Cr(OH)3------> 6(Cro4)2- +24H2O + 3I- + 18OH-Then by simplifying we get he balanced equation as IO3 - + 3H2O+2Cr(OH)3 -----> 2Cro4 2- 8 H2O +I- 6OH-