Question

Balanced equation for dilute sulphuric acid reacts with sodium carbonate

Answer 1

Answer:

Explanation:

This is the reaction. 0.02 Normal sulphuric acid is 0.01 M , pH of solution should be neutralized at the time you added same amount of sodium carbonate, or carbondioxide emission should be stopped. Na2CO3+H2SO4→Na2SO4+H2O+CO2↑，with indicator to see the final point！

Answer 2

Explanation:

Carbonates react with strong acids to form a salt, carbon dioxide gas, and water. The molecular equation for the reaction betweensodium carbonate and sulfuric acid is: 1. Na2CO3(aq)+H2SO4(aq)→Na2SO4(aq)+CO2(g)+H2O(l) N a 2 C O 3 ( a q ) + H 2 S O 4 ( a q ) → N a 2 S O 4 ( a q ) + C O 2 ( g ) + H 2 O ( l ) .