Question

Ball A rolled in a straight line with speed 5 metre per second towards up bigger ball B lying 20 metre away. After collision with ball B ball A retraces the path and reaches its starting point with the speed of 4 metre per second . Find the magnitude of the average velocity of Ball A and its average speed during the time interval (1.) 0 to 4 second (2.) 0 to 9 second and (3.) 0to 6 second

Answer 1

Answer:

The average velocity can be expressed as a relation between the whole way and the total time required for that way

         V(avg)= S(tot)/t(tot)

The total time in 6 sec and the total time must be calculated:

t(AB)= S(AB)/v(AB)

        = 20m/5m/s

       = 4 sec

Thus, the rest 2 sec the ball will travel, from B to some point C in betweenn B and A:

S(BC)= t(BC)* v(BC)

     = 2 sec* 4 m/s

   = 8 m

The total way for the 6 sec will be 28 m

 V(avg)= S(tot)/t(tot)

           = 28m/6 sec

     =   4.67m/s

Answer 2

Answer:5m/s is the required answer

Explanation:

See the attachment for the explanation