Math, asked by eklavyasingh2286, 6 months ago

ball at rest is made to roll with an acceleration of 2cms-², what will be velocity of ball after 3 sec?

Answers

Answered by harihar51

Step-by-step explanation:

using v=u+at

v=0+2x3

v=6cm/s

thank you

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Answered by pkst

Answer:

initial velocity=0 as ball was at rest

acceleration=2cm/s

time =3seconds

using

$distance = ut + \frac{1}{2} a {t}^{2}$

$d = 0 + 1 \times 9$

d=9cm

$2as = {v}^{2} - {u}^{2}$

$2 \times 2 \times 9 = {v}^{2} - 0$

$36 = {v}^{2}$

$\sqrt{36} = v$

final velocity is

$6 \frac{cm}{s}$

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