Question

Ball dropped from height of 20m.velocity increases uniformly 10m/s-2.with what velocity will it strike the ground?

Answer 1

Explanation:

As the ball was dropped, u = 0

We know that

 v² = u² + 2as

      =   0 + 2x 10 x 20

      = 400 m/s

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Answer 2

Explanation:

Given that,

Distance(s)="20m"

Initial velocity(u)=0m/s

Accelaration="10m/s-2"

Using the relation Distance-Time

s=v2 - u2=2a

s= v2-0=2*10

20=v2-0=20

v2-0=20*20

v2=400(underoot)

v=20 m/s

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