Question

Ball is thrown at an angle with the horizontal. Its horizontal range is equal to its maximum height. This is possible only when the value of tan is

Answer 1

Given that the horizontal range and the maximum height of the projectile is equal in magnitude. So,

$\dfrac {u^2\sin (2\theta)}{g}=\dfrac {u^2\sin^2\theta}{2g}\\\\\\\sin (2\theta)=\dfrac {\sin^2\theta}{2}\\\\\\4\sin\theta\cos\theta=\sin^2\theta\\\\\\4\cos\theta=\sin\theta\\\\\\\boxed {\tan\theta=4}$