Question

ball is thrown upward with a speed of 100 meter per second show that the ball hit the ground with same speed after returning from highest point . Take g=10ms

Answer 1

Here Initial velocity(u) = 100m/sec
Here we can say Hmax= u²/2g=10000/20=500 metres
we know that velocity in Hmax will be 0.
The derivation is below:-
v²=2aS+u²
   = 2*(-10)*500+10000
   =(-10000)+10000
   =0

So velocity at Hmax will be 0.
Now again with the equation of motion under gravity that v = √2gh ( if u =0)

We can say that here v will be velocity at reaching the ground and u is velocity at Hmax.

So, v = √2*10*500
         =  √10000
         = 100m/sec

Therefore we can conclude with the fact that initial velocity is same as the velocity obtained at reaching the ground.

Answer 2

Answer:

hmmmm

Explanation:

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