Question

Ball is thrown vertically upwards with a velocity of 40 metre per second then velocity of the ball after 2 seconds will be​

Answer 1

$\sf GivEn \begin{cases} & \sf{Initial\; Velocity,\;u = \bf{40\;m/s}} \\ & \sf{Time,\;t = \bf{2\;s}} \end{cases}$

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$\setlength{\unitlength}{1mm}\begin{picture}(8,2)\thicklines\multiput(9,1.5)(1,0){50}{\line(1,2){2}}\multiput(35,7)(0,4){13}{\line(0,1){2}}\put(10.5,6){\line(3,0){50}}\put(35,60){\circle*{10}}\put(37,7){\large\sf{u = 40 m/s}}\put(37,55){\large\sf{v = 20.4 m/s}}\put(21,61){\large\textsf{\textbf{Ball}}}\put(43,40){\line(0, - 4){28}}\put(43,35){\vector(0,4){18}} \put(24, - 3){\large\sf{ \sf g = - 9.8 m/s^2 }}\end{picture}$

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${\underline{\sf{\bigstar\;Using\;First\;equation\;of\;motion\;:}}}$

$:\implies\sf v = u + at$

$:\implies\sf v = 40 + (- 9.8) \times 2$

$:\implies\sf v = 40 - 19.6$

$:\implies{\underline{\boxed{\sf{\purple{\;\;20.4\;m/s\;\;}}}}}\;\bigstar$

$\therefore\;{\underline{\sf{velocity\; of\: the\: ball \:after\: 2\: seconds \,will \:be\; \textbf{20.4\;m/s.}}}}$

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Answer 2

$\sf GivEn \begin{cases} & \sf{Initial\; Velocity,\;u = \bf{40\;m/s}} \\ & \sf{Time,\;t = \bf{2\;s}} \end{cases}$

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${\underline{\sf{\bigstar\;Using\;First\;equation\;of\;motion\;:}}}$

$:\implies\sf v = u + at$

$:\implies\sf v = 40 + (- 9.8) \times 2$

$:\implies\sf v = 40 - 19.6$

$:\implies{\underline{\boxed{\sf{\purple{\;\;20.4\;m/s\;\;}}}}}\;\bigstar$

$\therefore\;{\underline{\sf{velocity\; of\: the\: ball \:after\: 2\: seconds \,will \:be\; \textbf{20.4\;m/s.}}}}$

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