ball rises to surface with constant velocity in a liquid whose density is 4 times that of material of ball. the ratio of force of friction and weight of the ball is
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this may help answer is in the box
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SHM11:
what is this "W"
and"c"
weight of the mass
c represent it is constant
ohk. thnqqq
pls make this brainlist answer thanq
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The ratio of force of the friction and weight of the ball is 3:1
Density of the ball = 4 ( Given)
Since the ball is rising with a constant velocity, therefore
net force = 0
Buoyant force = viscous force + weight
Vpg + F = V ( 4p) g
FV = 3V pg
F/ weight = 3Vpg/ Vpg
= 3
Therefore, the frictional force or the viscous force of the liquid on the rising ball will be greater than the weight of the ball by the factor of 3.
Thus, the ratio will be 3:1.
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