Math, asked by 123sona, 1 year ago

please solve this question

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Answered by Aryanmalewar
1
hope it helps. . . . mark as brainliest answer
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Aryanmalewar: welcome mark as brainliest answer
Answered by RabbitPanda
1
Construction: Draw AP ⟂ BC



In Δ ADP,

AD2 = AP2 + DP2

AD2 = AP2 + (BP - BD)2

AD2 = AP2 + BP2 + BD2 - 2(BP)(BD)

AD2 = AB2 + (1/3 BC)2 - 2(BC/2)(BC/3)

AD2 = 7/9 AB2 (Since BC = AB)

9AD2 = 7AB2
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