Question

BAllED and BCllEF show that ABC = DEF ​

Answer 1

Answer

• DE intersect BC at P
• EF||BC & DP is transversal

• ∠ DEF = ∠ DPC . . . . . . . . ( i )

Now, AB||DP & BC is transversal

• ∠ DPC = ∠ ABC . . . . . . . ( ii )

From ( i ) & ( ii ),

we get :

• ∠ ABC = ∠ DEF

Hence , proved