Question

bandana is four times as old as had brother akash at present after 10 years she will be twice the age of her brother then their present ages are​

Answer 1

let the age of akash be x.

so, the age of bandana is x+4.

a/q

x+10=2(x+4+10)

x+10=2x+8+20

x-2x=8+20-10

-x=18

x=18

then the age of akash is = 18

then the age of bandana is x+4

=18+4=22

please fine a thanks

Answer 2

Answer:

Step-by-step explanation:

$\texttt{Let Akash's present age be x.}$

$\texttt{Then, Bandana's present age = 4x}$

$\large{\underline{\texttt{10 years later:}}}$

$\texttt{Akash's age = x+10}$

$\texttt{Bandana's age = 4x+10}$

$\huge{\texttt{A/q,}}$

$\mathtt{4x+10=2(x+10)}$

$\mathtt{4x+10=2x+20}$

$\mathtt{4x-2x=20-10}$

$\mathtt{2x=10}$

$\mathtt{x=\Large\frac{10\!\!\!\!/\;^5}{2\!\!\!/}}$

$\mathtt{x=5}$

$\Large{\texttt{Hence, Akash's age = x = \red{5yrs}}}$

$\Large{\texttt{and Bandana's age = 4x = \red{20yrs}}}$