Question

Bangalore and ooty are two stations 390 km apart. a train starts from bangalore at 10

a.m. and travels towards ooty at 65 kmph. another train starts from ooty at 11

a.m. and travels towards bangalore at 35 kmph. at what time do they meet?

Answer 1

by the time train starts from ooty, Bangalore train would have covered 65km.
at 11am distance between two trains is 390-65=325
relative speed= 65+35=100
time = 325/100= 3.25hr= 3hr 15min
therefore they will meet at 2:15pn

Answer 2

Answer:

Ans: The train meet at 2: 15 pm

Step-by-step explanation:

A and B are 390 km apart

Let the trains meet at a point O, in between A and B.

First train starts at 10:00 am and travels for one hr (t=1) to reach an intermediate P at 11.00 am.

Distance traveled in one hr = AP= 1 x 65 = 65 km

Remaining distance (PB) = 390–65 = 325 km

From 11.00 am first train continues from P and second train starts from B.

First train

Let PO= d; speed = 65 km/h

Travel time,

t1= d/65 ——(1)

Second train

Distance traveled = 325-d; speed = 35 km/h

Travel time,

t2= (325-d)/35 —-(2)

At the time when the trains meet at O,

t1=t2

d/65 = (325-d)/35

d = 845/4

t1 = (845/4)/65 = 3.25 h

Alternatively,

t2 = [325-(845/4)]/35 = 3.25 h

The meeting time = 11 .00 + 3 hr 15 min= 14.25 hr = 14 : 15

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