bankersadda 3. two boys a and b start at the same time to ride from delhi to meerut 60 km away. a travels 4 km an hour slower than b. b reaches merrut and at once turns back meeting a 12 km from meerut the speed of a was
Answers
distance traveled by a = 60 - 12 = 48 kms
distance traveled by b = 60 + 12 = 72 kms
let the speed of b was x kmph
speed of a was x - 4 kmph
time will be same in both the cases and when time is constant
D1/S1 = D2/S2
48/(x - 4) = 72/x
solving
48x = 72x - 288
72x - 48x = 288
24x = 288
x = 288/24
x = 12
so speed of a was x - 4 = 12 - 4 = 8 kmph
Speed of a = 8 km/hr
Step-by-step explanation:
Distance between Merrut & Delhi = 60 km
Distance covered by b = 60 + 12 = 72 km
Distnace Covered by a = 60 - 12 = 48 km
Time taken is Same
Speed of b = 72/t km/hr
Speed of a = 48/t km/hr
48/t = 72/t - 4
=> 48 = 72 - 4t
=> 4t = 24
=> t = 6
Speed of a = 48/6 = 8 km/hr
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