Bansi has 3 times as many rupees 2 coins as he has rupees 5 coins. If he has in all a sum of rupees 77,how many coins of each denominations does he have.
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Let no. of 2 rupee coin be 3(2)x = 6x
Let the no. of 5 rupee coin be 5(x) = 5x
According to the question sum of rupees = 77
Now 5x + 6x = 77
11x = 77
x = 7
So rupees made by 2 rupee coins = 6 × 7 = 42
No. of 2 rupee coins = 42÷2 = 21
Rupees made by 5 rupees coins = 5 × 7 = 35
No. of 5 rupee coins = 35÷5 =7
So there are 21 coins of 2rupees and 7 coins of 5 rupees.
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Let the no. of 5 rupee coin be 5(x) = 5x
According to the question sum of rupees = 77
Now 5x + 6x = 77
11x = 77
x = 7
So rupees made by 2 rupee coins = 6 × 7 = 42
No. of 2 rupee coins = 42÷2 = 21
Rupees made by 5 rupees coins = 5 × 7 = 35
No. of 5 rupee coins = 35÷5 =7
So there are 21 coins of 2rupees and 7 coins of 5 rupees.
Hope it helps you.
Pls mark it as brianliest.
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