Bansi lal has 3 times as many two rupees coins as the has five rupee coins . If he has in all a sum of $ ,77,how many coins of each denomination does he have?
Answers
Answered by
9
Answer:
Two rupees coins = 21
Five rupees coins = 7
Step-by-step explanation:
Let Bansi has five rupees coins = x
Then he have two rupees coins = 3x
We are given,
Total money with him = Rs. 77
Then, according to the question,
5(x) + 2(3x) = 77
=> 5x + 6x = 77
=> 11x = 77
=> x = 77/11 = 7
Hence, x = 7
So Bansi has
five-rupees coins = x = 7
two rupees coins = 3x = 21
Answered by
1
Answer:
Let Bansi has x coin.
So, coins of ₹2 = 2 * x = 2x
And coins of ₹5 = 5 * x = 5x
From given condition,
=> 3 * (2x) = 6x
Sum of coins = 6x + 5x = 11x
=> 11x = 77
=> x = 77 ÷ 11
=> x = 7
3x = 3 * 7 = 21
Coins of ₹2 = x = 7
Coins of ₹5 = 3x = 3 * 7 = 21
Verification:
=> 42 + 35
=> 77
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