Barriers are placed around trees.For each inch of trunk diameter the protection zone should have a radius of 4/3 feet find the area of this zone for a tree with trunk circumference of 63 inches
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circumference =2(pi)r = 63 inch
i.e. r =63/2(pi) = 10.0
protection zone= 4/3 feet= 16 inch
now the radius of protection zone will be R = 10+16 = 26 inch
area of total zone = 2(pi)26 = 163.28 inch²
i.e. r =63/2(pi) = 10.0
protection zone= 4/3 feet= 16 inch
now the radius of protection zone will be R = 10+16 = 26 inch
area of total zone = 2(pi)26 = 163.28 inch²
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