Base and altitude of triangular metal disc are 66 ,28 cm .by drilling circular hole through this metal disc, it's area reduced to one third . Find diameter of hole ( take only one side into consideration)
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Area of metal disc=66x28/2
=924cm2
1/3 of the area=924/3=308cm2
2/3 of area=616cm2
Area of the hole =616
616= πr^2
r^2 = 616/π = 616x7/22 = 196
r =v196=14
diameter =2r=2x14=28cm. Ans
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