Question

base circumference of cylinder is 220cm and height is 63cm then find its curved surface area is​

Answer 1

Ans:- Base circumference of cylinder = 220

= 2πr = 220 (since the base of cylinder is circular so we use the formula of circumference)

= 2×22/7×r = 220

= therefore r = 35

now,

C.S.A of cylinder = 2πrh

= 2×22/7×35×63

= 13860cm^2

= 1.386m^2

Answer 2

Answer:

GIVEN BASE CIRCUMFERENCE OF A CYLINDER=220cm

GIVEN HEIGHT OF THE CYLINDER=63cm

THEN CURVED SURFACE AREA OF THE CYLINDER=2πrh

=2×22/7×220×63

=2×22×220×9

=44×1980

=87120

THEN TOTAL SURFACE AREA OF THE CYLINDER=2πr(h+r)

=2×22/7×220(63+220)

=2×22/7×220×283(HERE INSTEAD OF TAKING 22/7 I WILL TAKE 3.14)

=2×3.14×220×283

=6.28×220×283

=1381.6×283

=390992.8

THEN VOLUME OF THE CYLINDER=

$\pi {r}^{2}h$

$22 \div 7 \times {220}^{2} \times 63$

$22 \times 48400 \times 63$

$1064800 \times 63 = 67082400$