BASE is a rectangle. Its diagonals intersect at O. Find x, if OB=5x+1 and OE=2x+4.
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Answered by
140
We know that in rectangle, length of both the diagonals remains same.
So, { from the given diagram }
Length of 1st diagonal = Length of 2nd diagonal
Length of AE = length of BS
{ From the diagram, AE = 2x + 4 and BS = 5x + 1 {
2x + 4 = 5x + 1
4 - 1 = 5x - 2x
3 = 3x

1 = x
Therefore the value of x satisfying the length of diagonals of rectangle BASE is 1 .
So, { from the given diagram }
Length of 1st diagonal = Length of 2nd diagonal
Length of AE = length of BS
{ From the diagram, AE = 2x + 4 and BS = 5x + 1 {
2x + 4 = 5x + 1
4 - 1 = 5x - 2x
3 = 3x
1 = x
Therefore the value of x satisfying the length of diagonals of rectangle BASE is 1 .
Answered by
62
Solution :
In a rectangle diagonals are
equal and bisect each other.
BS = AE
=> BS/2 = AE/2
=> OB = OE
=> 5x + 1 = 2x + 4
=> 5x - 2x = 4 - 1
=> 3x = 3
=> x = 3/3
=> x = 1
Therefore ,
x = 1
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