base of a right angled triangle is 4cm and hypotenuse is 5cm. find it's area.
Answers
Answered by
6
By hypotenuse theorem H2 = B2+P2
5*5 = 4*4 +P2
25 = 16 +P2
P2 = 25-16
P2 = 9
perpendicular =3 =height
by
1/2 * base * height
1/2 * 4*3
2*3 =6cm
5*5 = 4*4 +P2
25 = 16 +P2
P2 = 25-16
P2 = 9
perpendicular =3 =height
by
1/2 * base * height
1/2 * 4*3
2*3 =6cm
ckaurmomi123:
wrong ans
Answered by
7
Area of right angle triangle = 1/2 ×b ×h
B=base
H=height
Height is the other side.....
According to the hypotenuse Theorem,

Where, a= height, b= base and c= hypotenuse


![a = \sqrt[2]{9} a = \sqrt[2]{9}](https://tex.z-dn.net/?f=a+%3D+%5Csqrt%5B2%5D%7B9%7D+)
![\sqrt[2]{9} = 3.0 \sqrt[2]{9} = 3.0](https://tex.z-dn.net/?f=+%5Csqrt%5B2%5D%7B9%7D+%3D+3.0)
3
H=3
1/2 × 4 × 3= 6
So, the area of the triangle = 6 m^2
HOPE it helps you
☺️☺️☺️
B=base
H=height
Height is the other side.....
According to the hypotenuse Theorem,
Where, a= height, b= base and c= hypotenuse
3
H=3
1/2 × 4 × 3= 6
So, the area of the triangle = 6 m^2
HOPE it helps you
☺️☺️☺️
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