Question

Base of a triangle is 18 and height is 10. Base of another triangle is 5 and height

is 3. Find the ratio of areas of these triangles.​

Answer 1

Answer:

1. area of 1st triangle=1/2×18×10
2. =90
3. area of 2nd triangle=1/2×5×3
4. =7.5
5. ratio=90:7.5

Answer 2

Answer:

Answer :

Ratio is 12 : 1 of the area of both the triangle .

$\checkmark$Given:

$\textsf{Base of the first triangle = 18}$

$\textsf{Height of the first triangle = 10}$

$\textsf{Base of the second triangle = 5}$

$\textsf{Height of the second triangle = 3}$

$\checkmark$To find:

$\textsf{Ratio of the areas of these triangles}$

$\checkmark$Concept:

First find the area of these triangles . Then find their ratio of the areas of both the triangles .

$\checkmark$Taken:

• Area of the triangle :

$\boxed{A=\frac{H×B}{2}}$

Where ,

A = Area of the triangle

H = Height of the triangle

B = Base of the triangle

• Raito of the area of the triangles :

$\boxed{R=\frac{A1}{A2}}$

Where ,

R = Ratio

A1 = Area of the first triangle

A2 = Area of the second triangle

$\checkmark$Solution:

▪︎Area of the first triangle:

$Taken,A1=\frac{H×B}{2}$

$\Rightarrow{A1=\frac{18×10}{2}}$

$\Rightarrow{A1=\frac{180}{2}}$

$\Rightarrow{A1=90}$

So , area of first triangle is 90 .

▪︎Area of the second triangle:

$Taken,A2=\frac{H×B}{2}$

$\Rightarrow{A2=\frac{3×5}{2}}$

$\Rightarrow{A2=\frac{15}{2}}$

$\Rightarrow{A2=7.5}$

So , area of the second triangle is 7.5 .

___________________________________

¤ Now find their ratio :

$Taken,R=\frac{A1}{A2}$

$\Rightarrow{R=\frac{90}{7.5}}$

$\Rightarrow{R=\frac{12}{1}}$

$\Rightarrow{R=12:1}$

So , the ratio of the area of both the triangle is 12:1 .

Extra information:

☆ Area of the square:

$\boxed{A = S×S}$

Where ,

A = Area of the square

S = Length if one side of the square

☆ Area of the rectangle:

$\boxed{AR=L×B}$

Where ,

AR = Area of the rectangle

L = Length of the rectangle

B = Breadth of the rectangle

☆ Perimeter of the triangle:

$\boxed{Perimeter=Sum\:of\:all\:sides\:of\:the\:triangle}$