base of a triangle is 40cm longer than it's attitude .if the area of the triangle is 48sq.cm.the base of triangle is
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Let ,
Area of triangle =48cm²
base=b
altitude =h
According to question:-
=>b=h+4
Area of triangle =1/2×b×h
Putting the value
Now,
48cm²=1/2×(h+4)×h
=>48×2=h²+4h
=>96=h²+4h
=>0=h²+4h- 96
=>0=h²+12h-8h-96
=>0=h(h+12)-8(h+12)
=>0=(h+12)(h-8)
so,
h+12=0 or h-8=0
=>h=-12 or h=8
but length can't be negative.
so,b=h+4=8+4=12cm
Answer is 12 cm
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