Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.
Answers
Answered by
2
Step-by-step explanation:
we know that,
area of triangle = 1/2 × base × height
now,
case 1
Area of 1st triangle = 1/2 × 9 × 5
=> area of 1st triangle = 22.5
case 2
area of 2nd triangle = 1/2 × 10 × 6
=> area of 2nd triangle = 30
NOW,
area of 1st triangle : area of 2nd triangle :: 22.5 : 30
=> ratio = 22.5/30
= 225/300
= 9/12
= 3/4
hence, ratio of both triangles = 3:4
Answered by
8
Answer:
Here is your answer
Let the Base, height and area of the first triangle be b1, h1 and A1 respectively.
let the base, height and area of the second triangle be b2, h2 And A2 respectively.
b1=9 , h1=5 ,b2=10, and h2=6.
☆The ratio of the areas of two triangke is equal to the ration of the products of their bases and corresponding heights. ☆
A1/A2= b1*h1/b2*h2
A1/A2=9*5/10*6
A1/A2=3/4
The ratio of the areas of these triangles is 3:4.
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